## Time and Work Questions and Answers Part-4

1. A can do a piece of work in 20 days and B in 40 days. If they work together for 5 days, then the fraction of the work that is left is ?
a) $$\frac{5}{8}$$
b) $$\frac{8}{{15}}$$
c) $$\frac{7}{{15}}$$
d) $$\frac{1}{{10}}$$

Answer: a
Explanation: L.C.M of total work = 40
One day work of A = $$\frac{{40}}{{20}}$$ = 2 unit/day
One day work of B = $$\frac{{40}}{{40}}$$ = 1 unit/day
(A + B)'s one day work is (2 + 1) units
(A + B)'s 5 day work is 3 × 5 = 15 units
Work left = 40 - 15 = 25
Fraction of work left
\eqalign{ & = \frac{{{\text{Work left}}}}{{{\text{Total work}}}} \cr & = \frac{{25}}{{40}} \cr & = \frac{5}{8} \cr}

2. If there is a reduction in the number of workers in a factory in the ratio 15 : 11 and an increment in their wages in the rate 22 : 25, then the ratio by which the total wages of the workers should be decreased is =
a) 6 : 5
b) 5 : 6
c) 3 : 7
d) 3 : 5

Answer: a
Explanation:
 Earlier : Now No.of worker 15 : 11 Wages 22 : 25 Total wages 330 275 Total wages 6 : 5

3. x does $$\frac{1}{4}$$ of a job in 6 days. y completes rest of the job in 12 days. Then x and y could complete the job together in = ?
a) $${\text{9 days}}$$
b) $${\text{8}}\frac{1}{8}{\text{ days}}$$
c) $${\text{9}}\frac{3}{5}{\text{ days}}$$
d) $${\text{7}}\frac{1}{3}{\text{ days}}$$

Answer: c
Explanation: x does $$\frac{1}{4}$$ work in 6 days.
x does complete work in 6 × 4 = 24 days
y does complete the $$\frac{3}{4}$$ work in 12 days.
y does complete work in 12 × $$\frac{4}{3}$$ = 16 days
x and y together can complete a work in
\eqalign{ & = \frac{{16 \times 24}}{{16 + 24}} \cr & = \frac{{48}}{5} \cr & = 9\frac{3}{5}\,{\text{days}} \cr}

4. Reena, Aastha and Shloka can independently complete a piece of work in 6 hours, 4 hours and 12 hours respectively. If they work together, how much time will they take to complete that piece of work ?
a) 2 hours
b) 5 hours
c) 6 hours
d) 8 hours

Answer: a
Explanation:
\eqalign{ & {\text{Reena's 1 hour's work}} = \frac{1}{6}{\text{ }} \cr & {\text{Aastha's 1 hour's work}} = \frac{1}{4}{\text{ }} \cr & {\text{Shloka's 1 hour's work}} = \frac{1}{{12}}{\text{ }} \cr}
( Reena + Aastha + Shloka )'s 1 hour's work
\eqalign{ & = \frac{1}{4} + \frac{1}{6}{\text{ + }}\frac{1}{{12}} \cr & {\text{ = }}\frac{6}{{12}} \cr & = \frac{1}{2} \cr}
They together take 2 hours to complete the work.

5. Amit and Sumit can plough a field in 4 days. Sumit alone can plough the field in 6 days. In how many days will Amit alone plough the feild ?
a) 10 days
b) 12 days
c) 14 days
d) 15 days

Answer: b
Explanation:
\eqalign{ & {\text{Amit's 1 day's work }} \cr & = \left( {\frac{1}{4} - \frac{1}{6}} \right) \cr & = \frac{1}{{12}} \cr}
Amit alone can plough the field in 12 days.

6. Working efficiencies of P and Q for completing a piece of work are in the ratio 3 : 4. The number of days to be taken by them to complete the work will be in the ratio ?
a) 3 : 2
b) 2 : 3
c) 3 : 4
d) 4 : 3

Answer: d
Explanation: Since we know efficiency and time are inversely proportional to each other.
\eqalign{ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{\text{P}}:{\text{Q}} \cr & {\text{Efficiency }}3:4 \cr & {\text{Time }}\,\,\,\,\,\,\,\,\,\,{\text{ }}4:3 \cr}

7. 5 men can do a piece of work in 6 days while 10 women can do it in 5 days. In how many days can 5 women and 3 men do it ?
a) 4 days
b) 5 days
c) 6 days
d) 8 days

Answer: b
Explanation:
\eqalign{ & {\text{5M}} \times {\text{6 days}} = {\text{10W}} \times {\text{5 days}} \cr & {\text{3M}} = {\text{5W}} \cr & \frac{{\text{M}}}{{\text{W}}} = \frac{5}{3} \cr & 1{\text{M}}\left( {{\text{work}}} \right) = 5{\text{ units/day}} \cr & {\text{1W}}\left( {{\text{work}}} \right) = 3{\text{ units/day}} \cr & {\text{Total work}} \cr & = \left( {{\text{5M}} \times {\text{6}}} \right) \cr & = {\text{5}} \times {\text{5}} \times {\text{6}} \cr & = {\text{150 units}} \cr & {\text{Required time for }}\left( {{\text{5W}} + {\text{3M}}} \right) \cr & = \frac{{{\text{Total work}}}}{{{\text{Work done/day}}}} \cr & = \frac{{150}}{{\left( {5 \times 3 + 3 \times 5} \right)}} \cr & = \frac{{150}}{{30}} \cr & = 5{\text{ days}} \cr}

8. A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With the help of C, they did the job in 4 days only. Then, C alone can do the job in ?
a) $${\text{9}}\frac{1}{5}{\text{ days}}$$
b) $${\text{9}}\frac{2}{5}{\text{ days}}$$
c) $${\text{9}}\frac{3}{5}{\text{ days}}$$
d) $${\text{10 days}}$$

Answer: c
Explanation:
\eqalign{ & \left( {{\text{A}} + {\text{B}} + {\text{C}}} \right){\text{'s 1 day's work}} = \frac{1}{4} \cr & {\text{A's 1 day's work}} = \frac{1}{{16}} \cr & {\text{B's 1 day's work}} = \frac{1}{{12}} \cr & {\text{C's 1 day's work}} \cr & = \frac{1}{4} - \left( {\frac{1}{{16}} + \frac{1}{{12}}} \right) \cr & = \left( {\frac{1}{4} - \frac{7}{{48}}} \right) \cr & = \frac{5}{{48}} \cr & {\text{So, C alone can do the work in }} \cr & = \frac{{48}}{5} \cr & = 9\frac{3}{5}{\text{ days}} \cr}

9. A can complete $$\frac{1}{3}$$ of a work in 5 days and B, $$\frac{2}{5}$$ of the work in 10 days. In how many days both A and B together can complete the work ?
a) $${\text{7}}\frac{1}{2}$$
b) $${\text{8}}\frac{4}{5}$$
c) $${\text{9}}\frac{3}{8}$$
d) 10

Answer: c
Explanation: Whole work will be done by A in
\eqalign{ & = \left( {5 \times 3} \right) \cr & = 15{\text{ days}} \cr}
Whole work will be done by B in
\eqalign{ & = \left( {10 \times \frac{5}{2}} \right) \cr & = 25{\text{ days}} \cr}
\eqalign{ & {\text{A's 1 day's work}} = \frac{1}{{15}} \cr & {\text{B's 1 day's work}} = \frac{1}{{25}} \cr & \left( {{\text{A}} + {\text{B}}} \right){\text{'s 1 day's work}} \cr & {\text{ = }}\left( {\frac{1}{{15}} + \frac{1}{{25}}} \right) \cr & = \frac{{16}}{{150}} \cr & = \frac{8}{{75}} \cr}
A and B together can complete the work in
\eqalign{ & = \frac{{75}}{8} \cr & = 9\frac{3}{8}{\text{days}}{\text{.}} \cr}

10. If 3 men or 6 women can do a piece of work in 16 days, in how many days can 12 men and 8 women do the same piece of work ?
a) 4 days
b) 5 days
c) 3 days
d) 2 days

Answer: c
Explanation:
\eqalign{ & {\text{3m}} \times {\text{16}} = {\text{6w}} \times {\text{16}} \cr}
$$\frac{{\text{m}}}{{\text{w}}} =$$ $$\frac{{2 \to {\text{Efficiency of men}}}}{{1 \to {\text{Efficiency of women}}}}$$
\eqalign{ & {\text{Total work}} = 3 \times 2 \times 16 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 96{\text{ units}} \cr}
$${\text{One day work of}}$$    $$\left( {{\text{12m}} + {\text{8w}}} \right)$$
\eqalign{ & = 12 \times 2 + 8 \times 1 \cr & = 32{\text{ units}} \cr}
$${\text{Total time taken by}}$$    $$\left( {{\text{12m}} + {\text{8w}}} \right)$$
\eqalign{ & = \frac{{96}}{{32}} \cr & = 3{\text{ days}} \cr}