Design of Steel Structures Questions and Answers Part-37

1. What is the value of non dimensional slenderness ratio λ in the equation of design compressive strength?
a) (fy /fcc)
b) √(fy fcc)
c) √(fy /fcc)
d) (fy fcc)

Answer: c
Explanation: The value of non dimensional slenderness ratio λ in the equation of design compressive strength is given by λ = √(fy /fcc) , where fy is yield stress of material and fcc = (π2E)/(KL/r)2, where E is modulus of elasticity of material and KL/r is effective slenderness ratio i.e. ratio of effective length.

2. The design compressive strength in terms of stress reduction factor is given by
a) Xfy
b) Xfy / γm0
c) X /fy γm0
d) Xfy γm0

Answer: b
Explanation: The design compressive strength in terms of stress reduction factor is given by fcd = Xfy / γm0 , where X = stress reduction factor for different buckling class, slenderness ratio and yield stress = 1/ [φ + (φ22)0.5], fy is yield stress of material and γm0 is partial safety factor for material strength.

3. The value of design compressive strength is limited to
a) fy + γm0
b) fy
c) fy γm0
d) fy / γm0

Answer: d
Explanation: The value of design compressive strength is given by fcd = [fy / γm0] / [φ + (φ22)0.5] ≤ fy / γm0 i.e. fcd should be less than or equal to fy / γm0.

4. The compressive strength for ISMB 400 used as a column for length 5m with both ends hinged is
a) 275 kN
b) 375.4 kN
c) 453 kN
d) 382 kN

Answer: b
Explanation: K = 1 for both ends hinged, KL = 1×5000 = 5000, r = 28.2mm (from steel table), Ae = 7846 mm2(from steel table)
KL/r = 5000/28.2 = 177.3
h/bf = 400/140 = 2.82, t = 16mm Therefore, buckling class = b
From table in IS code, fcd = 47.85MPa
Pd = Ae fcd = 7846 x 47.85 = 375.43 kN.

5. What is beam?
a) structural member subjected to transverse loads
b) structural member subjected to axial loads only
c) structural member subjected to seismic loads only
d) structural member subjected to transverse loads only

Answer: a
Explanation: Beam is a structural member subjected to transverse loads that is loads perpendicular to its longitudinal axis. The mode of deflection of beam is primarily by bending.

6. Structural members subjected to bending and large axial compressive loads are known as
a) strut
b) purlin
c) beam-column
d) lintel

Answer: c
Explanation: Structural members subjected to bending accompanied by large axial compressive loads at the same time are known as beam-column. A beam-column differs from column only by presence of eccentricity of load application, end moment, transverse load.

7. What is girt?
a) vertical beam spanning between wall column of industrial buildings
b) horizontal beam spanning between wall column of industrial buildings
c) vertical beam spanning between wall column of residential buildings
d) horizontal beam spanning between wall column of residential buildings

Answer: b
Explanation: Girt is horizontal member fastened to and spanning between peripheral column of industrial buildings. It is used to support wall cladding such as corrugated metal sheet.

8. Members used to carry wall loads over wall openings are called
a) purlin
b) rafter
c) girder
d) lintels

Answer: d
Explanation: Lintels are beam members used to carry wall loads over wall openings for doors, windows, etc.

9. Load transfer by a beam is primarily by
a) bending only
b) shear only
c) bending and shear
d) neither bending nor shear

Answer: c
Explanation: The load transfer by beam is primarily by bending and shear. The mode of deflection of beam is primarily by bending.

10. What are spandrels?
a) exterior beams at floor level of buildings
b) interior beams at floor level of buildings
c) exterior columns
d) interior columns

Answer: a
Explanation: Spandrels are exterior beams at floor level of buildings, which carry part of floor load and exterior wall.