1. There are two types of loading. The uniformly distributed and the non-uniformly distributed that is the one having two different values at corners.
a) The first part of the statement is false and other part is true
b) The first part of the statement is false and other part is false too
c) The first part of the statement is true and other part is false
d) The first part of the statement is true and other part is true too
Explanation: The two forms of the loading are the uniformly distributed and the non-uniformly distributed that is the one having two different values at corners. The uniform distributed load is not having two different values of the load per unit meter on the corner.
2. The type of reduction of the loading is different for the uniformly distributed and the non-uniformly.
a) True
b) False
Explanation: The methods for the reduction of the loadings are different for both uniformly distributed and the non-uniformly. In the latter, the simplification uses the quadratic equation. The latter also uses the integration for the same purpose.
3. In the simplification of the loading system, the net force acts at the ___________ of the loading body.
a) Centroid
b) The centre axis
c) The corner
d) The base
Explanation: In the simplification of the loading system the net force acts at the centroid of the loading body. That is if the loading system is in the form of the triangle then the at the distance 2 by 3 of the base the net force of the loading will act. And the load will be half the area of the loading.
4. In triangle distributed loading, the loading at any distance can be easily found by using which of the following trigonometry function?
a) Tangent
b) Sine
c) Cosine
d) Sine inverse
Explanation: In triangle distributed loading, the loading at any distance can be easily found by using Tangent trigonometry function. That is because the linear distance only determines the vertical loading. That is the loading is uniform along the linear distance. Is the linear distance is more the loading is more
5. If the non-Uniform loading is of the type of parabola then?
a) The net load will not be formed as all the forces will be cancelled
b) The net force will act the centre of the parabola
c) The net force will act on the base of the loading horizontally
d) The net force will act at the centroid of the parabola
Explanation: The net force will act at the centroid of the parabola. Whether it be a parabola or the cubic curve the centroid is the only point at which the net force act. Force can’t be acted horizontally if the loading is vertical. Hence whatever be the shape of the loading, the centroid is the point of action of net force.
6. If any external force also is applied on the distributed loading then?
a) The net force will act at the centroid of the structure only
b) The net load will not be formed as all the forces will be cancelled
c) The net force will act on the base of the loading horizontally
d) The net force will not to be considered, there would be a net force of the distribution, rest will be the external forces
Explanation: The external forces are treated differently. They are not added by the force of the distributed loading. That is the force not only acts at the centroid always. It can be shifted also. Depending on the external forces
7. The resultant force acting, of the uniformly distributed loading, is dependent on:
a) Area
b) Vertical distance
c) Length of the supports
d) The distance of the supports between them
Explanation: The resultant force acting, of the uniformly distributed loading, is dependent on the area that the distribution is covering. The more the area the more is the force. That is the more is the tension created over the structure on which loading is kept. Hence the answer.
8. The difference between the two types of loading namely uniformly distributed and the non-uniformly distributed loading is that:
a) The latter has the involvement of the integration for the calculation of the net force
b) The former has the involvement of the integration for the calculation of the net force
c) The latter has the involvement of the differentiation for the calculation of the net force
d) The former has the involvement of the differentiation for the calculation of the net force
Explanation:The non-uniformly distributed loading is using the integration for getting the net force given by it. And the former only need the area or the linear distance of the loading. That is when the distance is multiplied by the uniformly distributed load the net force is obtained. But that is not so with the non-uniform one.
9. The main condition for the rigid body is that the distance between various particles of the body does change.
a) True
b) False
Explanation: The main condition for the rigid body is that the distance between various particles of the body does not change. If the distance does change the body is not to be called as rigid. Thus the fix distance of the particles is very much required for the equilibrium of the rigid body.
10. What does Newton’s third law states?
a) The rate of change of momentum is equal to the force applied
b) For every reaction, there is an opposite reaction
c) The body tends to be rotated if the force is applied tangentially
d) The body is rest until a force is applied
Explanation: The requirement of the third law is important in the equilibrium of the body. Especially the rigid bodies. The rigid body particles are in the equilibrium and are thus facing the forces and to be in the equilibrium they also react and apply the opposite force and thus the third law of Newton.