1. Sound velocity is maximum in
a) \[H_{2}\]
b) \[N_{2}\]
c) He
d) \[O_{2}\]
Explanation:
2. The minimum distance of reflector surface from
the source for listening the echo of sound is
a) 28 m
b) 18 m
c) 19 m
d) 16.5 m
Explanation:
3.The type of waves that can be propagated through
solid is
a) Transverse
b) Longitudinal
c) Both (a) and (b)
d) None of these
Explanation: Since solid has both the properties (rigidity and elasticity)
4. A man stands in front of a hillock and fires a gun.
He hears an echo after 1.5 sec. The distance of the
hillock from the man is (velocity of sound in air is
330 m/s)
a) 220 m
b) 247.5 m
c) 268.5 m
d) 292.5 m
Explanation: If d is the distance between man and reflecting surface of sound then for hearing echo
5. The speed of a wave in a medium is 760 m/s. If
3600 waves are passing through a point, in the
medium in 2 minutes, then its wavelength is
a) 13.8 m
b) 25.3 m
c) 41.5 m
d) 57.2 m
Explanation:
6. If at same temperature and pressure, the
densities for two diatomic gases are respectively
\[d_{1}\] and \[d_{2}\] , then the ratio of velocities of sound in
these gases will be
a) \[\sqrt{\frac{d_{2}}{d_{1}}}\]
b) \[\sqrt{\frac{d_{1}}{d_{2}}}\]
c) \[d_{1}d_{2}\]
d) \[\sqrt{d_{1}d_{2}}\]
Explanation:
7.The frequency of a tunning fork is 384 per second
and velocity of sound in air is 352 m/s. How far
the sound has traversed while fork completes 36
vibration
a) 3 m
b) 13 m
c) 23 m
d) 33 m
Explanation:
8. \[v_{1}\] and \[v_{2}\] are the velocities of sound at the same
temperature in two monoatomic gases of
densities \[\rho_{1}\] and \[\rho_{2}\] respectively. If \[\rho_{1}/ \rho_{2}=\frac{1}{4}\]
then the ratio of velocities v1 and v2 will be
a) 1 : 2
b) 4 : 1
c) 2 : 1
d) 1 : 4
Explanation:
9.The temperature at which the speed of sound in
air becomes double of its value at \[0^{\circ}C\] is
a) 273K
b) 546K
c) 1092K
d) 0K
Explanation:
10. If wavelength of a wave is \[\lambda=6000\dot{A}\] . Then wave
number will be
a) \[166\times 10^{3} m^{-1}\]
b) \[16.6\times 10^{-1} m^{-1}\]
c) \[1.66\times 10^{6} m^{-1}\]
d) \[1.66\times 10^{7} m^{-1}\]
Explanation:
