Ionic Equilibrium Questions and Answers Part-1

1. The \[pK_{a}\] of a weak acid, HA, is 4.80. The \[pK_{b}\] of a weak base, BOH, is 4.78. The pH of an aqueous solution of the corresponding salt, BA, will be
a) 9.58
b) 4.79
c) 9.22
d) 7.01

Answer: d
Explanation: 7.01

2. What will be the value of pH of 0.01 mol \[dm^{-3}CH_{3}COOH \left[K_{a}=1.74\times10^{-5}\right]\]
a) 3. 4
b) 3. 6
c) 3. 9
d) 3. 0

Answer: a
Explanation: 3. 4

3. The pH of a solution which is 0.1 M in HA and 0.5 M in NaA. \[ K_{a}\] for HA is \[1.8\times10^{-6}\]
a) 5.44
b) 6.44
c) 6.0
d) 4.73

Answer: b
Explanation: 6.44

4. Which of the following will produce a buffer solution when mixed in equal volumes?
a) 0.1 mol \[dm^{-3}NH_{4}OH \]    and 0.1 mol \[dm^{-3}HCl \]
b) 0.05 mol \[dm^{-3}NH_{4}OH \]    and 0.1 mol \[dm^{-3}HCl \]
c) 0.1 mol \[dm^{-3}NH_{4}OH \]    and 0.05 mol \[dm^{-3}HCl \]
d) 0.1 mol \[dm^{-3}CH_{4}COONa \]      and 0.1 mol \[dm^{-3}NaOH \]

Answer: c
Explanation: 0.1 mol \[dm^{-3}NH_{4}OH \]    and 0.05 mol \[dm^{-3}HCl \]

5.A solution which is \[10^{-3} \] M each in \[Mn^{2+}, Fe^{2+},Zn^{2+}\]     and \[Hg^{2+}\]   is treated with \[10^{-6} \] M sulphide ion. If \[K_{sp}\] of MnS, FeS, ZnS and HgS are \[10^{-15} \] , \[10^{-23} \] , \[10^{-20} \] and \[10^{-54} \] respectively which one will precipitate first
a) FeS
b) MgS
c) HgS
d) ZnS

Answer: c
Explanation: HgS

6. Which will not affect the degree of ionization?
a) Temperature
b) Concentration
c) Type of solvent
d) Current

Answer: d
Explanation: Current does not effect the degree of ionisation

7. At infinite dilution, the percentage ionisation for both strong and weak electrolytes is
a) 1%
b) 20%
c) 50%
d) 100%

Answer: d
Explanation: Ionisation is 100% at infinite dilution

8.A 0.2 molar solution of formic acid is 3.2% ionized. Its ionisation constant is
a) \[9.6 × 10^{-3}\]
b) \[2.1 × 10^{-4}\]
c) \[1.25 × 10^{-6}\]
d) \[4.8 × 10^{-5}\]

Answer: b
Explanation:
q8

9. The hydrogen ion concentration of 0.2 N \[CH_{3}COOH\]   which is 40% dissociated is
a) 0.08 N
b) 0.12 N
c) 0.80 N
d) 1.2 N

Answer: a
Explanation:
q9

10. Degree of dissociation of 0.1 N CH3COOH is (Dissociation constant = \[1 × 10^{-5})\]
a) \[ 10^{-5}\]
b) \[ 10^{-4}\]
c) \[ 10^{-3}\]
d) \[ 10^{-2}\]

Answer: d
Explanation: \[ 10^{-2}\]